x − P e t e r ′ s roc k s 3 x − P hi l ′ s roc k s x + 3 x = 48 4 x = 48 ∣ : 4 x = 12 3 x = 3 ⋅ 12 = 36 36 − 12 = 24 P hi l ha v e 24 m ore roc k s t han P e t er .
The question involves solving a problem where Phil has three times as many rocks as Peter, and together they own 48 rocks. To find out how many more rocks Phil has than Peter, we need to set up an equation and solve it. Let's denote the number of rocks Peter has as P. Then, Phil has 3 × P rocks. If we combine both quantities, we have P + 3P = 48, which simplifies to 4P = 48. Dividing both sides by 4 gives P = 12. Therefore, Peter has 12 rocks and Phil has 3 × 12 = 36 rocks. To find out how many more rocks Phil has, we subtract Peter's amount from Phil's: 36 - 12 = 24 rocks.
Phil has 36 rocks while Peter has 12 rocks. This means that Phil has 24 more rocks than Peter. The solution involves setting up an equation based on the relationships described in the problem.
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