How do you factor [tex]2x^2 + 5x - 12[/tex]?

so you find out what two numbers add up to 5 and multiply to make -12 so since -12 is negative we know that the two numbers have to be diffarent signs (- times+=-)
also we see that the X^2 term is 2x^2 so we can use the 2 so the factored out form is (2x+3)(x-4) because the 2x times -4=-8x the 3 times the x=3x add them together and get 3x+(-8x)or 5x which is our middle term and -4 times 3 =-12 which is our last term

Answered by apologiabiology | 2024-06-10

easier
multiply -12 by two to get -24
what goes into -24 and adds to make 5? -3 and 8
so the equation is 2X^2 + 8X -3X -12
this can cancel down to 2X(X+4)-3(X+4)
gather the terms to get (2X-3)(X+4)

Answered by dlasham154 | 2024-06-10

To factor 2 x 2 + 5 x − 12 , identify coefficients, multiply a and c to get -24, find numbers that sum to 5 and multiply to -24 (8 and -3), rewrite the expression, group, and factor. The final factored form is ( 2 x − 3 ) ( x + 4 ) .
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Answered by apologiabiology | 2024-12-26