Solve the following equations:

1. \(6x + 8 = 50\)

2. \(2x - 5 = 11\)

3. \(13 = -4x + 9\)

4. \(7 - 3x = 34\)

2 x − 5 = 11 ∣ a dd 5 2 x = 16 ∣ d i v i d e b y 2 x = 8 13 = − 4 x + 9 ∣ s u b t r a c t 9 4 = − 4 x ∣ d i v i d e b y − 4 x = − 1 7 − 3 x = 34 ∣ s u b t r a c t 7 − 3 x = 27 ∣ d i v i d e b y − 3 x = − 9

Answered by luana | 2024-06-10

6x=8
x=8/6=4/3

6x=50
x=50/6=25/3

2x-5=11
2x=16
x=8

13=-4x+9
4x=9-13
4x=-4
x=-1

7-3x=34
3x=7-34
3x=-27
x=-9

Answered by Anonymous | 2024-06-10

The solutions to the equations are as follows: x = 7 for the first equation, x = 8 for the second, x = − 1 for the third, and x = − 9 for the fourth. Each solution was obtained by performing inverse operations to isolate x .
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Answered by luana | 2024-12-26