Horses are measured in units called hands. One inch equals \(\frac{1}{4}\) hand. The average Clydesdale is 17 \(\frac{1}{5}\) hands tall.
What is the height in inches? In feet?
Answer (3)
1 inch = 1/4 hand, that means 1 hand = 1*4 = 4 inch. 17 1/5 = [85 + 1]/5 = 86/5, 86/5 hand = 86/5 * 4 = 344/5 = 68.8 inch, 1 feet = 12 inch, 68.8 inch = 68.8/12 = 5.73 feet. Avg. Clydesdale height = 17 1/5 hand = 68.8 inch = 5.73 feet.
Clydesdale is 17 1/5 hands tall then the height in inches is 68.8 inches and the height in feet is 5.73ft and this can be determined by using arithmetic operations and the unitary method .
Given :
Horses are measured in units called hands.
One inch equals 1/4 hand.
The average Clydesdale is 17 1/5 hands tall.
The following steps can be used to determine the height in inches :
Step 1 - Clydesdale height in hands unit is:
17 5 1 = 5 86
Step 2 - Now, if one inch equals 1/4 hands then 86/5 is equal to:
= 4 1 5 86
Step 3 - Multiply 86/5 and 4/1.
= 5 86 × 1 4
Step 4 - Multiply 86 and 4.
= 5 × 1 344
Step 5- Further simplify the above expression.
= 68.8 inches
Now, to convert inches in feet use:
1 inch = 0.08333 feet
So, if 1 inch is equal to 0.0833 feet then 68.8 inches is equal to:
= 1 68.8 × 0.0833
= 5.73 ft .
For more information, refer to the link given below:
https://brainly.com/question/24406804
The average height of a Clydesdale horse is 68.8 inches, which is approximately 5.73 feet. This was calculated by converting the height from hands to inches and then from inches to feet. The process involved using basic multiplication and division related to unit conversions.
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