The width of a rectangle is five less than twice the length. What is the minimum area of the rectangle?

W=2L-5

A=L*W
=L(2L-5)
=2L²-5L

dA/dL=4L-5
When dA/dL=0,
4L-5=0
4L=5
L=5/4

When L=5/4
A=5/4*(2*(5/4)-5)
=5/4*(10/4-20/4)
=5/4*((-10)/4)
=5/4*(-5/2)
**=-25/8 **
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*You may have been given a badly written out question. The answer doesn't make sense.
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Answered by Anonymous | 2024-06-10

To find the minimum area of a rectangle where the width is defined as five less than twice the length, we set up the area function. However, solving leads to an invalid negative width, indicating that no valid rectangle meets the given conditions. This suggests a potential issue in the problem setup.
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Answered by Anonymous | 2024-10-02