How do you prove [tex](3x+2)^2[/tex] is equivalent to [tex](3x+6)(3x-2)+16[/tex]?

( 3 x + 2 ) 2 = 9 x 2 + 12 x + 4 ( 3 x + 6 ) ( 3 x − 2 ) + 16 = 9 x 2 − 6 x + 18 x − 12 + 16 = 9 x 2 + 12 x + 4

Answered by konrad509 | 2024-06-10

We can prove that ( 3 x + 2 ) 2 is equivalent to ( 3 x + 6 ) ( 3 x − 2 ) + 16 by expanding both expressions. After expanding and simplifying, both yield the same result, confirming their equivalence. This shows that in algebra, different expressions can represent the same quantity when manipulated correctly.
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Answered by Anonymous | 2024-12-26