{ − x = − y − 6 ∣ ∗ ( − 1 ) x + 2 y = 12 { x = y + 6 x + 2 y = 12 u s in g s u b s t i t u t i o n m e t h o d y + 6 + 2 y = 12 3 y + 6 = 12 ∣ s u b t r a c t 6 3 y = 6 ∣ d i v i d e b y 3 y = 2 x = y + 6 = 2 + 6 = 8 { x = 8 y = 2
Using the substitution method, we found that the solution to the system of equations is x = 8 and y = 2 . We rearranged the second equation to express x in terms of y and substituted it into the first equation to solve for y . Finally, we substituted back to find x .
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