A = lw P = 2 l + 2 w
30 = lw 34 = 2 l + 2 w
30 = lw --> w = l 30
34 = 2 l + 2 ( l 30 ) 34 = 2 l + l 60 34 l = 2 l 2 + 60 2 l 2 − 34 l + 60 = 0 2 ( l − 2 ) ( l − 15 ) = 0 l = 2 , 15
30 = ( 2 ) w 15 = w
30 = ( 15 ) w 2 = w
The dimensions can either be 15 x 2 or 2 x 15 .
The dimensions of the rectangle are 15 meters by 2 meters or 2 meters by 15 meters. Both configurations satisfy the area of 30 square meters and a perimeter of 34 meters. This is derived from the equations for area and perimeter of a rectangle.
;