300 mi l es o n 12 , 5 g a ll o n s x mi l es o n 42 g a ll o n s M akin g p ro p or t i o n : 300 − 12 , 5 x − 42 C ross m u lt i pl i c a t i o n 300 ∗ 42 = 12 , 5 x 12600 = 12 , 5 x ∣ d i v i d e b y 12 , 5 x = 1008 He c an d r i v e 1008 mi l es o n 42 g a ll o n s o f g a s .
Jayson can drive 1008 miles on 42 gallons of gasoline. This is calculated by setting up a proportion based on his car's fuel efficiency. After solving the proportion, we find that he can drive a significant distance with the amount of gas he has.
;