A dance floor is made from square wooden tiles with a side length of 1 foot. The floor can be laid out as a square or as a rectangle. Yeasmin chooses a rectangular dance floor for her party.

- The width of the rectangular dance floor is 10 feet less than the width of the square dance floor.
- The length of the rectangular dance floor is 15 feet greater than the length of the square dance floor.

1. How much greater is the length of the rectangular dance floor than its width?

2. The perimeter of the rectangular dance floor is 130 feet. What are the length and width of the dance floor?

3. If the unit rate is $0.50 per tile, how much would it cost Yeasmin to buy the number of tiles needed to make up the dance floor?

Let x be the original width of the square dance floor.
In the rectangle: Length = x + 15 Width = x - 10 Therefore, the difference between length and width = 25.
Perimeter = 2length + 2width 130=2(x + 15) + 2(x - 10) 130=2x + 30 + 2x -20 130 = 4x + 10 130 - 10 = 4x x = 120/4 x = 30 Length = x + 15 = 30 + 15 = 45 Width = x - 10 = 30 - 10 = 20 Therefore, the length of the dance floor is 45 feet and the width is 20 feet
The number of tiles is the area of the dance floor because each tile is 1 foot by 1 foot. Area = length * width Area = 45 * 20 Area = 900 feet² Thus, she needs 900 tiles. Each tiles costs 0.50 so , T o t a l cos t = 900 t i l es ∗ 0.50 = $450.00

Answered by chipperrider | 2024-06-10

The length of the rectangular dance floor is 25 feet greater than its width, with dimensions of 45 feet in length and 20 feet in width. The tiles needed cost Yeasmin $450 in total. Each tile costs $0.50 and the area of the floor is 900 square feet.
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Answered by chipperrider | 2025-06-17