lets use substitution y=7x-10 y=-3
so -3=7x-10 7=7x 1=x
now lets check y=7(1)-10 y=-3
therefore both equations have the same value
To solve the system of equations using substitution, we first identify one equation where either x or y is already isolated. In our case, we have the equation y = -3.
We can now substitute this value of y into the other equation to find the value of x.
If the system is: 7x - 2y = 24 3x + 9y = 30 First, we can solve the second equation for x:
3x + 9(-3) = 30 3x - 27 = 30 3x = 57 x = 19
Now that we have the value of x, we can substitute it into the first equation to find y:
7(19) - 2y = 24 133 - 2y = 24 2y = 133 - 24 2y = 109 y = 54.5
Thus, the solution to the system of equations is x=19, y=54.5.
The solution to the system of equations y = 7 x − 10 and y = − 3 using substitution is x = 1 and y = − 3 . We substituted y in the first equation and solved for x , then confirmed the solution by checking both equations. Therefore, the final solution is ( 1 , − 3 ) .
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