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In Mathematics / High School | 2014-11-09

A school play sells adult and child tickets. On Friday, they sold 55 child tickets and 20 adult tickets for $200. On Saturday, they sold 72 child tickets and 36 adult tickets for $306.

What is the cost of each individual ticket?

Please show your work for the following answers:

1. $1 per child ticket and $7.25 per adult ticket
2. $1 per child ticket and $6.50 per adult ticket
3. $2 per child ticket and $4.50 per adult ticket

Asked by garagajo3

Answer (2)

Let's make the price of tickets for adults x and children y, now form an equation Friday - 55y + 20x = 200 Saturday - 72y + 36x = 306 Now you have to have either the x or the y cancel out, so you have to find the relationship between two of them I am going to multiply the top equation by 9/5 to cancel out the x 99y + 36x = 360 72y + 36x = 306 Now I am going to multiply the bottom equation by -1 -72y - 36x = -306 99y + 36x = 360 The x cancel out 27y = 54 y = 2 So the price of a child ticket is $2 Now plug 2 into one of the original equations 55(2) + 20x = 200 20x = 90 x = 4.5 The price of an adult ticket is $4.50

Answered by theapplezoo | 2024-06-10

The price of each child ticket is $2, and the price of each adult ticket is $4.50. Thus, the correct answer is option 3: $2 per child ticket and $4.50 per adult ticket.
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Answered by theapplezoo | 2024-10-02

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