Solve by substitution:

\[ y = 6x - 11 \]

\[ -2x - 3y = -7 \]

so you substitute y=6x-11 into -2x-3y=-7
-2x-3(6x-11)=-7 add like terms -20x+33=-7 subtract 33 from both sides -20x=-40 multiply by -1 20x=40 divide both sides by 20 x=2

Answered by apologiabiology | 2024-06-10

y = 6 x − 11 − 2 x − 3 y = − 7 s u b s t i t u t e y = 6 x − 11 in t o e q u a t i o n − 2 x − 3 ( 6 x − 11 ) = − 7 ∣ o mi t t h e b r a c k e t − 2 x + 18 x + 33 = − 7 16 x + 33 = − 7 ∣ s u b t r a c t 33 16 x = − 40 ∣ d i v i d e b y 16 x = − 16 40 ​ = − 2 5 ​ y = 6 x − 11 = 6 ∗ ( − 2 5 ​ ) − 11 = − 15 − 11 = − 26 S o l u t i o n : { x = − 2 5 ​ y = − 26 ​

Answered by luana | 2024-06-10

By substituting the expression for y from the first equation into the second equation, we find that x = 2 and y = 1. Therefore, the solution to the system of equations is (2, 1). We checked the solution, and it satisfies both equations.
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Answered by apologiabiology | 2024-12-26