Joaquin has created a small treasure map that is in the shape of a square. He decides to make a larger version of the map, and on this new map, he increases each side by 6 inches. The area of this larger version of the map is 121 square inches.

What are the dimensions of his original, smaller map?

(l+6)(l+6)=121=l^2+6l+6l+36 l^2+12l-85=(l-5)(l+17) l=5 or l =-17 cannot be negative therefore was a 5 by 5 map

Answered by DavidShotter | 2024-06-25

The length of a side of the smaller map is 5 inches. ;

Answered by Limosa | 2024-06-26

The dimensions of Joaquin's original smaller treasure map are 5 inches for each side. When the sides are increased by 6 inches, the larger map has an area of 121 square inches. This is confirmed by calculating the area of the larger map using its new side length of 11 inches.
;

Answered by Limosa | 2024-09-17