The area of a rectangle is 21 m², and the length of the rectangle is 1 m less than twice the width. Find the dimensions of the rectangle.

This should be right because I checked it afterwards Width=W Length=2W-1 The equation is as follows W(2W-1)=21 2 W 2 -W=21 Subtract 21 from each side 2 W 2 -W-21 Group them/put them in parentheses..can't think of the right word right now (2W-7)(W+3) -7=I7I You only do this for the first parenthese, 7÷2W=3.5 W=3.5 If W=3.5 then 2W-1⇒2×3.5-1⇒7-1⇒6 Length=6 If W=3.5 and L=6, then W(2W-1)=21 3.5(2×3.5-1)=21 Solve in parentheses first 3.5(7-1)=21 3.5(6)=21 3.5×6=21 The width is 3.5 The length is 6

Answered by Geekhawk | 2024-06-10

The width of the rectangle is 3.5 meters, and the length is 6 meters. This was determined by setting up a quadratic equation based on the given area and the relationship between length and width. The calculations confirm that the area is indeed 21 m².
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Answered by Geekhawk | 2024-12-26