a = s(1-dn) a = s - sdn a - s = -sdn a - s = (-sd)n (a-s) รท (-sd) = n
The **equation **in terms of N is given by N=1/D-A/DS
What are linear equations?
Linear equations help in **representing **the relationship between variables such as x, y, and z, and are expressed in **exponents **of one degree. In these linear equations , we use algebra, starting from the basics such as the addition and subtraction of **algebraic **expressions.
Given here: A=S(1-DN)
Therefore **solving **for x we get
A=S(1-DN)
A/s=1-DN
DN=1-A/S
N=1/D-A/DS
Hence, the **equation **in terms of N is given by N=1/D-A/DS
Learn more about linear expressions here:
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To solve for N in the equation A = s ( 1 โ D N ) , rearrange to isolate N and obtain the final expression N = sD s โ A โ . This involves distributing and basic algebraic manipulation. It's an important skill for high school mathematics students.
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