For the school play, advance tickets cost $3, while tickets at the door cost $5. Thirty more tickets were sold at the door than in advance, and $2630 was collected.
How many of each kind of ticket were sold?
Answer (2)
x − n u mb er o f t i c k e t s x + 30 − n u mb er o f t i c k e t s a t t h e d oor 3 x + 5 ( x + 30 ) = 2630 3 x + 5 x + 150 = 2630 3 x + 5 x = 2630 − 150 8 x = 2480 ∣ : 8 x = 310 310 + 30 = 340 A d v an ce t i c k e t s w ere 310 an d o t h er t i c k e t s w ere 340.
The student sold 310 advance tickets and 340 tickets at the door. This was determined by setting up and solving an equation based on the ticket prices and total revenue collected. The equations were simplified step-by-step to find the values for each type of ticket sold.
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