A barge travels twice as fast when it is empty as when it is full. If it travels 20 miles north with a cargo, spends 20 minutes unloading, and returns to its original port empty, taking 8 hours to complete the entire trip, what is the speed of the barge when it is empty?

V1=(empty)=2 v2(full) 20+20 (go+return) t1+t2=8hour-20’(1/3 hour)=23/3hour t1=23/3-t2 v1 t1+v2 t2=20+20 2v2 (23/3-t2)+v2 t2=40 2v2 23/3-2v2 t2+v2t2=40 2v2 23/3-v2t2=40 2v2 23/3-20=40 2v2 23/3=60 v2=60/46/3=180/46=90/23 v1=2*90/23=180/23

Answered by Anonymous | 2024-06-10

Answer:wada ;

Answered by wyliek08 | 2024-06-12

The speed of the barge when it is empty is approximately 7.83 mph. The speed when it is loaded is about 3.91 mph. The calculation involved using the distances traveled and the total time for the trip to establish relationships between the speeds.
;

Answered by Anonymous | 2024-09-30