The acceleration of a particle is given by the equation \( A = 3t \).

If \( V = 2 \, \text{m/s} \) at \( t = 1 \, \text{sec} \) and \( S = 12 \, \text{m} \) at \( t = 1 \, \text{sec} \), find \( S \) at \( t = 2 \, \text{sec} \).

EDIT: MY ANSWER ASSUMED CONSTANT ACCELERATION - CHANGING IT NOW

Answered by ollieboyne | 2024-06-10

The position of the particle at t = 2 sec is 16 meters after calculating the velocity and position equations based on the given acceleration. We derived the equations by integrating the acceleration and used known values to solve for constants. Finally, substituting t = 2 sec into the position equation yields the result.
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Answered by ollieboyne | 2024-12-26