A sound wave travels at 330 m/sec and has a wavelength of 2 meters.

Calculate its frequency and period.

frequency=velocity/wavelength 330/2=165 hertz period=1/frequency=1/165 second

Answered by fandn | 2024-06-10

The frequency of the wave with a** speed** of 330 m/s and 2 meter wavelength is 165 Hz. The time period of the wave is then, 0.006 seconds.
What is frequency ?
Frequency of a wave is the number of wave cycles per second. Frequency of a wave is the inverse of its time period. It is inversely proportional to the wavelength and directly proportional to the speed.
Hence, ν = c/λ, where c is the speed.
The frequency of a sound wave is called its pitch .
Given that, c = 330 m/s
wavelength λ = 2 meters.
frequency = 330/2 = 165 s⁻¹ or 165 Hz.
The time period of a wave = 1/ frequency.
T = 1/165 = 0.006 s or 6 milliseconds.
Therefore, the** frequency **of the wave is 165 Hz and time period is 0.006 seconds.
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Answered by kanikabajaj294 | 2024-06-17

The frequency of the sound wave is 165 Hz, and its period is approximately 0.00606 seconds (or 6.06 milliseconds).
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Answered by kanikabajaj294 | 2024-09-30