In 2003, the population of Zimbabwe was about 12.6 million, which was 1 million more than 4 times the population in 1950.

Write and solve an equation to find the population \( p \) of Zimbabwe in 1950.

Let's set the population of Zimbabwe in 1950 equal to x.
So in 2003, the population was 12.6 million. So our equation should equal 12.6 million. Here's how you turn the other parts of the problem into an equation: 4x + 1m = 12.6 m
Now to solve.
4x = 12.6m - 1m 4x = 11.6m x = 11.6m/4 x = 2.9m In 1950, the population was 2.9 million

Answered by TylerK | 2024-06-10

The population of Zimbabwe in 1950 can be found by setting up and solving the equation 12.6 = 4 p + 1 . After solving, we find that the population was approximately 2.9 million. This calculation shows how we can use algebra to relate past and present population figures.
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Answered by TylerK | 2024-12-26