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In History / High School | 2014-11-02

What is the time interval between the release of the ball and the time it reaches its maximum height?

The acceleration due to gravity is 9.81 m/s\(^2\) and the maximum height is 4.4 m.

Neglect air resistance.

Asked by tassybieber

Answer (3)

We are going to use a kinematics equation and the knowledge that the maximum height of a projectile is achieved when the velocity in the y direction equals 0.
d = vt - (1/2)at² d = -(1/2)at² -2d/a = t² t = √((-2 * 4.4)/(-9.81)) t = √0.897 t = 0.95s

Answered by chipperrider | 2024-06-10

The** time interval** between the release of the ball and when it reaches its maximum height can be calculated by finding the initial velocity with the equation 'v = √(2gh)', and then applying this to 't = v / g'. This gives the time it takes in seconds. ;

Answered by StefaniJoanne | 2024-06-18

The time interval for the ball to reach its maximum height of 4.4 m is approximately 0.946 seconds. This was calculated using kinematic equations involving initial velocity and acceleration due to gravity. The initial velocity was found to be around 9.30 m/s.
;

Answered by StefaniJoanne | 2024-12-26