We are going to use a kinematics equation and the knowledge that the maximum height of a projectile is achieved when the velocity in the y direction equals 0.
d = vt - (1/2)atΒ² d = -(1/2)atΒ² -2d/a = tΒ² t = β((-2 * 4.4)/(-9.81)) t = β0.897 t = 0.95s
The** time interval** between the release of the ball and when it reaches its maximum height can be calculated by finding the initial velocity with the equation 'v = β(2gh)', and then applying this to 't = v / g'. This gives the time it takes in seconds. ;
The time interval for the ball to reach its maximum height of 4.4 m is approximately 0.946 seconds. This was calculated using kinematic equations involving initial velocity and acceleration due to gravity. The initial velocity was found to be around 9.30 m/s.
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