Solve the system of equations:

1. \(2X + Y = 7\)

2. \(3X - 4Y = 5\)

{ 3 x − 4 y = 5 2 x + y = 7 ∣ ∗ 4 ​ { 3 x − 4 y = 5 8 x + 4 y = 28 ​ + − − − − A dd i t i o n m e t h o d 11 x = 33 ∣ d i v i d e b y 11 x = 3 y = 7 − 2 x y = 7 − 2 ∗ 3 = 7 − 6 = 1 S o l u t i o n : { x = 3 y = 1 ​

Answered by luana | 2024-06-10

To solve the system of equations 2 X + Y = 7 and 3 X − 4 Y = 5 , we use the elimination method. We find that X = 3 and Y = 1 . Therefore, the solution to the system is { X = 3 , Y = 1 } .
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Answered by luana | 2024-12-16