How many mg of a metal containing 45% nickel must be combined with 6 mg of pure nickel to form an alloy containing 78% nickel?

let's call the mass of 45% nickel x.
45x + (100 x 6) = 78 x total mass
the total mass is 6 + x, so:
45x + 600 = 78(6 + x) 45x + 600 = 468 + 78x 600-468 = 78x - 45x 132 = 33x x = 132/33 x = 4 g
hope this helps :)

Answered by ollieboyne | 2024-06-10

To create an alloy containing 78% nickel, you need to combine 4 mg of the metal containing 45% nickel with 6 mg of pure nickel. This can be determined by setting up a mass equation based on the percentages. The calculation shows that the amount needed of 45% nickel is 4 mg.
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Answered by ollieboyne | 2024-09-27