The geometric sequence of the missing points is:
a is the missing points initially. Assuming 100 marks, this is 25
r = 8/10, as the missing marks reduces by 2/10 each time
u n = 25 ( 10 8 ) n − 1
Assuming the marks are out of 100, and marks are rounded to the nearest whole number, the maximum mark he can get is 98 , as 2/10 of the remaining 2 marks would make it 98.4, which would round back to 98.
This series is converging, as the 8/10 gets smaller every time, so the series will eventually converge.
Hope this helps :)
Phillip can recover the missing 25 points through a geometric series with a sum of recoverable points converging to 25, resulting in a maximum score of 100. The series is converging because the common ratio is less than 1. Thus, he is able to achieve a perfect score on his project.
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