Write the equation of a parabola with the vertex at the origin and the focus at (0, -1/32).

-b/2a = 0 => b = 0; -Δ/4a = -1/32, where Δ = b 2 − 4 a c = − 4 a c => -4ac/4a = -1/32 => c = 1/32, where a is not 0 => equation of parabolasVertex at origin, Focus (0,-1/32) is y = a x 2 + 1/32;

Answered by crisforp | 2024-06-10

The equation of the parabola with vertex at the origin and focus at (0, -1/32) is y = − 8 x 2 . This equation indicates that the parabola opens downwards. The value of a was determined using the distance from the vertex to the focus.
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Answered by crisforp | 2024-12-23