What is the velocity of a 500-kilogram elevator that has 4,000 joules of energy?

E = 2 m v 2 ​ 2 E = m v 2 v 2 = m 2 E ​ v = m 2 E ​ ​ v = 500 8000 ​ ​ v = 16 ​ v = 4 4 meters per second.

Answered by Anonymous | 2024-06-10

The velocity of the 500-kilogram elevator with 4,000 joules of energy is 4 meters per second, calculated using the kinetic energy formula. By rearranging the formula and substituting the values, we derived the velocity step-by-step. This calculation is essential in understanding how kinetic energy relates to mass and speed.
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Answered by Anonymous | 2024-12-20