A roadside vegetable stand sells pumpkins for $5 each and squashes for $3 each. One day, they sold 6 more squashes than pumpkins, and their sales totaled $98.

Write and solve a system of equations to find how many pumpkins and squashes they sold.

Let's take those 6 squashes. You get 98-6*3=80. Now you have an identical number of pumpkins and squashes. A pumpkin and a squash are sold, in total, for $8, so to get $80 you need 10 of each. You have 10 pumpkins and 10+6=16 squashes.

Answered by Anonymous | 2024-06-10

The roadside vegetable stand sold 10 pumpkins and 16 squashes, based on the given total sales and the relation between the quantities sold. The system of equations solved was S = P + 6 and 5 P + 3 S = 98 . By substituting and solving, we found the quantities sold for each vegetable.
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Answered by Anonymous | 2024-12-20