The larger of two numbers is ten more than twice the smaller number. The sum of the numbers is forty. What is the original number? Solve and check.

okay, so what this means is that the larger number is 10 + 2x and the smaller number is x put them together and set them equal to forty. 10+3x=40 subtract ten from both sides. 3x=30 devide both sides by three x=10 now you have the smaller number, so plug it back in to the equation we said was the bigger number. 10+2(10) The larger number is 30.

Answered by Jaybird | 2024-06-10

first lets represent x will be the smaller number while the larger one is 2x+10 so their sum is 40 so x+2x+10=40 3x+10=40 3x=30 x=10
so the smaller one is 10 while the larger is 2x+10 2(10)+10 20+10 =30
hope this answeres you problem :)

Answered by deathstrike001 | 2024-06-10

The smaller number is 10 and the larger number is 30. This satisfies the conditions that the larger number is ten more than twice the smaller number and that their sum is forty.
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Answered by Jaybird | 2024-12-23