Graph the line using intercepts:

4x - 3y = 12

First you have to find the intercepts!
To find the y-intercept (I usually do that first), pretend x=0. Then it becomes: 4(0)-3y=12 Which then becomes: -3y=12. Divide both sides, and y = -4. Then the (x,y) coordinate would become (0, -4).
Next you would find the x-intercept, and pretend y = 0. Which then becomes: 4x-3(0)=12 3x0 cancels out to become: 4x = 12 And x = 3 because division stuffs. Then THIS point would then be (3,0).
So then, you would plot (0,-4) and (3,0) on a graph and connect the points! I attached a picture for reference.
hope that helped~

Answered by hwangj1999 | 2024-06-10

Graph the intercepts by assigning the balue to y or x then after u assign u will graph it. Since it is a linear equation it might be easier so it may be a line not a parabola

Answered by deathstrike001 | 2024-06-10

To graph the line 4 x − 3 y = 12 , first find the y-intercept by setting x = 0 which gives the point ( 0 , − 4 ) . Then, find the x-intercept by setting y = 0 , giving the point ( 3 , 0 ) . Plot these points and draw a line through them to represent the equation.
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Answered by hwangj1999 | 2024-10-16