A photon has an energy of [tex]2.93 \times 10^{-25} \, \text{J}[/tex].
What is its frequency? What type of electromagnetic radiation is this photon?
Answer (2)
The equation given by Planck's follows:
E = h ν
where,
E = energy of the light = 2.93 × 1 0 − 25 J
h = Planck's constant = 6.62 × 1 0 − 34 J s
ν = frequency of light = ?
Putting values in above equation, we get:
2.93 × 1 0 − 25 J = 6.62 × 1 0 − 34 J s × ν ν = 6.62 × 1 0 − 34 J s 2.93 × 1 0 − 25 J = 4.43 × 1 0 9 Hz
The relation between frequency and wavelength is given as:
ν = λ c
where,
c = the speed of light = 3 × 1 0 8 m / s
ν = frequency of radiation = 4.43 × 1 0 8 s − 1
λ = wavelength of the radiation = ?
Putting values in above equation, we get:
4.43\times 10^{8}s^{-1}=\frac{3\times 10^8m/s}{\lambda}\\\\\lambda=\frac{3\times 10^8m/s}{4.43\times 10^8}s^{-1}}=0.677m
The radiation having wavelength 0.677 m belongs to radio waves.
Hence, the radiation has a frequency of 4.43 × 1 0 9 Hz and is a type of radio wave.
The photon has a frequency of approximately 4.42 × 10⁸ Hz, indicating that it represents radio waves. We calculated this using Planck's equation, showing the relationship between energy and frequency. Thus, the photon falls into the category of radio electromagnetic radiation.
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