How many atoms are in 0.750 moles of zinc?
Answer (3)
(doesn't really matter that it's zinc :) ) It is 0.75 ∗ N A , where N A = 6.023 ∗ 1 0 23 (in some books 6.022).
There are approximately 4.52 x 10^23 **atoms **in 0.750 moles of zinc .
How to find the number of atoms
To determine the **number **of atoms in a given amount of a substance, you can use Avogadro's number , which is approximately 6.022 x 10^23 atoms/mol.
Given that you have 0.750 moles of zinc, you can calculate the number of atoms using the following steps:
Multiply the given number of moles by Avogadro's number:
0.750 moles * (6.022 x 10^23 atoms/mol) = 4.5165 x 10^23 atoms
Round the result to an appropriate number of significant figures:
Since the value given has three significant figures, the final answer should be rounded accordingly. Therefore, the number of atoms in 0.750 moles of zinc is approximately 4.52 x 10^23 atoms.
So, there are approximately 4.52 x 10^23 atoms in 0.750 moles of zinc.
Learn more about **zinc **at
https://brainly.com/question/1594082
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There are approximately 4.52 × 1 0 23 atoms in 0.750 moles of zinc. This is calculated by multiplying the number of moles by Avogadro's number. The calculation maintains three significant figures based on the moles given.
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