When converting cotangent+5 into cos/sin do you do what I did and bring the 5 with them or do you do cos/sin +5?

(cosx/sinx) + 5 =(cosx + 5sinx)/sinx;

Answered by crisforp | 2024-06-10

When converting cotangent + 5 into ⅔/sin, you separate the cotangent term and the constant. The cotangent function is equivalent to the quotient of cosine over sine (⅔/sinθ), so when you add 5 to cotangent, it becomes (⅔/sinθ) + 5. You do not bring the 5 along with the ⅔ and sin within the same fraction. Instead, you keep the constant term separate from the trigonometric function.
An example of a trigonometric identity involving cosine and sine is: sin² θ + cos² θ = 1, which demonstrates the fundamental Pythagorean relationship between sine and cosine, often used when dealing with trigonometric expressions.

Answered by RandleMcMurphy | 2024-06-24

When converting cot ( x ) + 5 to cosine and sine, write it as s i n ( x ) c o s ( x ) ​ + 5 . The constant +5 should be treated separately from the cotangent function. This keeps your mathematical expression clear and accurate.
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Answered by RandleMcMurphy | 2024-12-26