Two dice are rolled. What is the probability that the sum of the numbers rolled is greater than or equal to 5?

2 + 3 = 5 > = 5; 2 + 4 = 6 > =5; 2 + 5 = 7 >= 5; 2 + 6 = 8 >= 5; 3+2 = 5 >= 5; 3 + 3 = 6 >= 5; 3 + 4 = 7 >= 5; 3 + 5 = 8 >= 5; 3 + 6 = 9 >= 5; 4+1 = 5 >= 5; 4+2 = 6 >= 5; 4+3 = 7 >= 5; 4+4 = 8 >= 5; 4+5 = 9 >= 5; 4+6 = 10 >= 5; 5+1 = 6 >= 5; 5+2 = 7 >= 5; ..............
6 + 6 = 12 >= 5;
Number of ways it can happen = 27;
Total number of outcomes = 6*6 = 36;
Probability of an event happening = Number of ways it can happen / Total number of outcomes => Probability = 27/36 = 0.75;

Answered by crisforp | 2024-06-10

Answer:1/3 ;

Answered by ashlynn11051994 | 2024-06-12

The probability that the sum of the numbers rolled on two dice is greater than or equal to 5 is 6 5 ​ . This is calculated by finding that there are 30 successful outcomes out of a total of 36 possible outcomes when rolling two dice. Thus, the probability is 36 30 ​ .
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Answered by crisforp | 2024-12-23