A speedy river barge bound for New Orleans, Louisiana, leaves Baton Rouge at 9:00 a.m. and travels at a speed of 10 miles per hour. A rail transport freight, also bound for New Orleans, leaves Baton Rouge at 1:30 p.m. on the same day. The train travels at 25 miles per hour. Both the barge and the train will travel 100 miles to reach New Orleans. How far will the train travel before catching up to the barge?

okay i get it now

At 1.30 p.m. the barge has already traveled 4.5 X 10 = 45 miles.

To catch up it will take the train 25-10 = 15miles

Answered by Anonymous | 2024-06-10

A rail transport freight train also bound for New Orleans leaves Baton Rouge at 1;30 PM on the same day. The train travels at 25 MPH and the river barge travels at 10 MPH. ... the barge leaves at 9:00 am so that would be at 9 hours past midnight. the train leaves at 1:30 pm so that would be at 13.5 hours past midnight. ;

Answered by james129724 | 2024-06-12

The train travels 75 miles before catching up to the barge. This is determined by calculating the time it takes to close the initial gap created by the barge's head start. The train, traveling faster, takes 3 hours to make up the 45 miles that the barge has already traveled.
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Answered by Anonymous | 2024-10-31