How many magnesium ions are present in [tex]5.36 \times 10^{-4}[/tex] mol of magnesium iodide?
Answer (2)
magnesium iodide = MgI₂ mass of Mg = 24.3g mass of I = 126.9g mass of MgI₂ = 24.3 + 2*126.9 = 278.1g = 1 mole
in 5.36x10⁻⁴ mole of MgI₂ ---------------- x g of Mg in 1 mole of MgI₂ ------------------------------ 1 mole of Mg x = 5.36x10⁻⁴ moles of Mg = 0.000536 moles of Mg
answer: we've 0.000536 moles of Mg (magnesium ions) in 5.36x10⁻⁴ moles of MgI₂
There are approximately 3.22 × 10²⁰ magnesium ions in 5.36 × 10⁻⁴ mol of magnesium iodide. This is calculated by recognizing that each mole of MgI₂ contains one mole of Mg²⁺ ions and then using Avogadro's number to convert moles to individual ions. Thus, the total number of magnesium ions is derived from the moles of MgI₂ provided.
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